5y-2-[6-(3-y)]=4(y-3)+7

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Solution for 5y-2-[6-(3-y)]=4(y-3)+7 equation:


Simplifying
5y + -2 + -1[6 + -1(3 + -1y)] = 4(y + -3) + 7
5y + -2 + -1[6 + (3 * -1 + -1y * -1)] = 4(y + -3) + 7
5y + -2 + -1[6 + (-3 + 1y)] = 4(y + -3) + 7

Combine like terms: 6 + -3 = 3
5y + -2 + -1[3 + 1y] = 4(y + -3) + 7
5y + -2 + [3 * -1 + 1y * -1] = 4(y + -3) + 7
5y + -2 + [-3 + -1y] = 4(y + -3) + 7

Reorder the terms:
-2 + -3 + 5y + -1y = 4(y + -3) + 7

Combine like terms: -2 + -3 = -5
-5 + 5y + -1y = 4(y + -3) + 7

Combine like terms: 5y + -1y = 4y
-5 + 4y = 4(y + -3) + 7

Reorder the terms:
-5 + 4y = 4(-3 + y) + 7
-5 + 4y = (-3 * 4 + y * 4) + 7
-5 + 4y = (-12 + 4y) + 7

Reorder the terms:
-5 + 4y = -12 + 7 + 4y

Combine like terms: -12 + 7 = -5
-5 + 4y = -5 + 4y

Add '5' to each side of the equation.
-5 + 5 + 4y = -5 + 5 + 4y

Combine like terms: -5 + 5 = 0
0 + 4y = -5 + 5 + 4y
4y = -5 + 5 + 4y

Combine like terms: -5 + 5 = 0
4y = 0 + 4y
4y = 4y

Add '-4y' to each side of the equation.
4y + -4y = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 4y + -4y

Combine like terms: 4y + -4y = 0
0 = 0

Solving
0 = 0

Couldn't find a variable to solve for.

This equation is an identity, all real numbers are solutions.

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